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ASP FAQ Tutorials :: Databases :: Other Articles :: How do I present one-to-many relationships in my ASP page?


How do I present one-to-many relationships in my ASP page?

Often you need to show results from multiple tables in one unified interface. Let's say you have the following schema (geared to SQL Server): 
 
CREATE TABLE artist 

    [id] INT IDENTITY, 
    [name] VARCHAR(32) 

 
CREATE TABLE album 

    [artist_id] INT, 
    [name] VARCHAR(32) 

 
INSERT INTO artist(name) VALUES('Michael Jackson') 
INSERT INTO artist(name) VALUES('ABBA') 
INSERT INTO artist(name) VALUES('Tragically Hip') 
 
INSERT INTO album(artist_id,name) VALUES(1,'Bad') 
INSERT INTO album(artist_id,name) VALUES(1,'Very Bad - Worst Hits') 
 
INSERT INTO album(artist_id,name) VALUES(2,'Gold') 
 
INSERT INTO album(artist_id,name) VALUES(3,'Self-Titled') 
INSERT INTO album(artist_id,name) VALUES(3,'Up to Here') 
INSERT INTO album(artist_id,name) VALUES(3,'Road Apples') 
INSERT INTO album(artist_id,name) VALUES(3,'Fully Completely') 
INSERT INTO album(artist_id,name) VALUES(3,'Day For Night') 
INSERT INTO album(artist_id,name) VALUES(3,'Trouble at the Henhouse') 
INSERT INTO album(artist_id,name) VALUES(3,'Live Between Us') 
INSERT INTO album(artist_id,name) VALUES(3,'Phantom Power') 
INSERT INTO album(artist_id,name) VALUES(3,'Music@Work') 
 
The results you want in ASP are: 
 
ABBA 
            Gold 
 
Michael Jackson      
            Bad 
            Very Bad - Worst Hits 
 
Tragically Hip 
            Self-Titled 
            Up to Here 
            Road Apples 
            Fully Completely 
            Day For Night 
            Trouble at the Henhouse 
            Live Between Us 
            Phantom Power 
            Music@Work 
 
Now, what I see many people attempting in ASP is something like this (and I'll keep HTML simple for brevity): 
 
<% 
    sql = "SELECT id,name FROM artist ORDER BY name" 
    set rs = conn.execute(sql) 
    do while not rs.eof 
        response.write rs("name") & "<p>" 
        sql2 = "SELECT name FROM album WHERE artist_id=" &_ 
            rs("id") & " ORDER BY name" 
 
        set rs2 = conn.execute(sql2) 
        do while not rs2.eof 
            response.write rs2("name") & "<br>" 
            rs2.movenext 
        loop 
        response.write "<br>" 
        rs.movenext 
    loop 
%>
 
There are much more efficient ways to do this than creating multiple recordsets and nesting them. This is what joins are for. Imagine the above code if you then had a table with the song titles on the album? And then another table listing the bands who have covered each song? And then a table further to that listing the albums of each of THOSE bands? 
 
Creating nested recordsets is very inefficient. Let's look at the join solution to the above: 
 
<% 
    sql = "SELECT " &_ 
        "artistName = artist.name, " &_ 
        "albumName = album.name " &_ 
    "FROM " &_ 
        artist, " &_ 
        album " &_ 
    "WHERE " &_ 
        "artist.id = album.artist_id " &_ 
    "ORDER BY " &_ 
        "artist.name, " &_ 
        "album.name" 
 
    currentArtist = "" 
    set rs = conn.execute(sql) 
    do while not rs.eof 
        if rs("artistName") <> currentArtist then 
            response.write rs("artistName") & "<p>" 
            currentArtist = rs("artistName") 
        end if 
        response.write rs("albumName") & "<br>" 
        rs.movenext 
    loop 
%>
 
One recordset, getting all your results, without causing extra strain on the database by executing multiple statements consecutively. One large recordset is always more efficient than multiple recordsets obtaining the same amount of data. 
 
Now, one problem you might come acrosss is, what if an artist has no albums, but you still want to show the artist name? Imagine adding the following artist, who couldn't possibly have any record deals in effect: 
 
INSERT INTO artist(name) VALUES('Aaron Bertrand')
 
Now, the query and ASP code to still return this value is as follows (note how little it changes): 
 
<% 
    sql = "SELECT " &_ 
        "artistName = artist.name, " &_ 
        "albumName = ISNULL(album.name,'-') " &_ 
    "FROM " &_ 
        "artist " &_ 
    "LEFT JOIN " &_ 
        "album " &_ 
    "ON " &_ 
        "artist.id = album.artist_id " &_ 
    "ORDER BY " &_ 
        "artist.name, " &_ 
        "album.name" 
 
    currentArtist = "" 
    set rs = conn.execute(sql) 
    do while not rs.eof 
        if rs("artistName") <> currentArtist then 
            response.write rs("artistName") & "<p>" 
            currentArtist = rs("artistName") 
        end if 
        if rs("albumname") <> "-" then 
            response.write rs("albumName") & "<br>" 
        else 
            response.write "No albums for this artist.<br>" 
        end if 
        rs.movenext 
    loop 
%>
 
We do a LEFT OUTER JOIN so that artists are included even if they have no matching rows in the albums title. 
 
Of course, we would use stored procedures here, however the above methodology will work against Access, MySQL, etc.

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Created: 1/23/2002 | Last Updated: 6/16/2005 | broken links | helpful | not helpful | statistics
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